Need help on grep command
Hi Team,
I have the below file .
ID Name Hours Worked Hourly Pay
1425 Juan 18 14.25
4321 George 22 21.11
6781 Anne 44 16.77
1451 Ben 36 21.77
2277 Tuan 16 18.77
I need help on the below comamnds on grep, Iam new to grep
I need to display the hourly pay of anne (only the last field )
using grep command.
Secondly , One line comamnd to find the id and hours worked for employees who earn more than $20 per hour.
I have the below file .
ID Name Hours Worked Hourly Pay
1425 Juan 18 14.25
4321 George 22 21.11
6781 Anne 44 16.77
1451 Ben 36 21.77
2277 Tuan 16 18.77
I need help on the below comamnds on grep, Iam new to grep
I need to display the hourly pay of anne (only the last field )
using grep command.
Secondly , One line comamnd to find the id and hours worked for employees who earn more than $20 per hour.
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Grep is a tool to match patterns
As others pointed out other tools, commands need to be used to meet your need.
Your second question
cat fileofdata.txt | awk ' ($4>=20) {print $2,$4 }'
The default when -F is not used to designate the delimiter to ve use to break up the data on a line is white space, which would include combinations of spaces, and I velum E tabs.
The condition is To evaluate whether the last column is greater than 20, iwhen it is the name and the hourly is reported.
Where is this data coming from, it might be better to search through the source if database, or similar....
As others pointed out other tools, commands need to be used to meet your need.
Your second question
cat fileofdata.txt | awk ' ($4>=20) {print $2,$4 }'
The default when -F is not used to designate the delimiter to ve use to break up the data on a line is white space, which would include combinations of spaces, and I velum E tabs.
The condition is To evaluate whether the last column is greater than 20, iwhen it is the name and the hourly is reported.
Where is this data coming from, it might be better to search through the source if database, or similar....
grep Anne <file> | cut -f4
Again, if tab delimited the second one should be:
grep [2-9][0-9]\.[0-9][0-9] <file> | cut -f1
I have a feeling though that your file isn't tab delimited.