How to code CMYK numbers into an Excel VBA procedure

I have CMYK numbers to use in an excel worksheet.
How can I code CMYK numbers into range("a1").font.color?
brothertruffle880Asked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Neil FlemingConsultant and developerCommented:
Code below performs an approximate conversion of CMYK to RGB. It's not perfect though. See original discussion (where I found this) at https://stackoverflow.com/questions/10690125/coloring-cells-in-excel-with-cmyk-cell-values

Function CYMK2RGB(c As Integer, y As Integer, m As Integer, k As Integer) As Long
Dim R As Integer
Dim G As Integer
Dim B As Integer
Dim colors As Integer

colors = 255 * (100 - k) / 100
R = colors * (100 - c) / 100
G = colors * (100 - m) / 100
B = colors * (100 - y) / 100

CYMK2RGB = RGB(R, G, B)
End Function

Open in new window

0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
brothertruffle880Author Commented:
Thanks Neil!!!!
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
VBA

From novice to tech pro — start learning today.