How to check if directory exist using asterisk in Bash

Hi Experts,
could you pls help me how to check if directory exist using asterisk "*" in bash "if condition".
Basically would like to check if directory exist like *Drop* or best solution please

Below is the sample script
cd /home/mobaxterm; mkdir tmp tmp1  Child_Drop1 Child_Drop2 Child_Drop3 Child_Drop4 Child_Drop5

base=/home/mobaxterm/tmp
base_dir="${base}/*Drop*"

ls -ltr "${base}/"*Drop*
cp -r  "${base}/"*Drop* ${base}/tmp1/

if [ -d "${base_dir}" ] ; then
  echo "drop exists"
  cp -r  "${base}/"*Drop* ${base}/tmp1/
else
  echo "drop do not exists"
fi

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Thanks in advance
enthuguyAsked:
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Ricardo CananiCommented:
base=/home/mobaxterm/tmp
base_dir="${base}/*Drop*"

if [ "$(ls -Ud $base_dir 2>/dev/null)" ] ; then
   echo "drop exists"
else
   echo "drop does not exist"
fi
0
nociSoftware EngineerCommented:
-d can only check one directory without wildcard
so you need to expand the wildcard...  Ricardo showed one way.

fnd=0
for i in ${base}/*Drop*
do
   [ -d $i ] && fnd=1
done
[ "$fnd" == "1" ] && echo "*Drop*" found...

Open in new window


you can also tell which one mached..
fnd=0
for i in ${base}/*Drop*
do
   [ -d $i ] && fnd=1 && echo Found: $i 
done
[ "$fnd" == "1" ] && echo "*Drop*" found...

Open in new window

0

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