how to color svg file in HTML?

dear experts

I want to use svg icon on my web page
I use bootsrap4 css and below code like this.

<img class="icon icon-account-login" src="img/svg/account-login.svg">

my css file is like this, but I see the icon but the colour is black not #f00
how can I color the svg picture?

.icon-account-login {
  fill: #f00;
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Julian HansenCommented:
You can't style SVG images loaded in an Image tag - only inline SVG can be styled.
BRMarketingAuthor Commented:
dear Julian Hansen,
can you give me an example please? how can I style it, change the color?
Julian HansenCommented:
how can I style it, change the color?
You can't - you would need to change the underlying SVG file.
Only when the SVG is in the page as
  ... <!-- SVG code here can be styled -->

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You could try the code below from this post to change your <img> SVG's into inline - but I would only use this if you need to change the background colour dynamically. If it is static then change it in the SVG file directly.
    var $img = jQuery(this);
    var imgID = $img.attr('id');
    var imgClass = $img.attr('class');
    var imgURL = $img.attr('src');

    jQuery.get(imgURL, function(data) {
        // Get the SVG tag, ignore the rest
        var $svg = jQuery(data).find('svg');

        // Add replaced image's ID to the new SVG
        if(typeof imgID !== 'undefined') {
            $svg = $svg.attr('id', imgID);
        // Add replaced image's classes to the new SVG
        if(typeof imgClass !== 'undefined') {
            $svg = $svg.attr('class', imgClass+' replaced-svg');

        // Remove any invalid XML tags as per
        $svg = $svg.removeAttr('xmlns:a');

        // Check if the viewport is set, if the viewport is not set the SVG wont't scale.
        if(!$svg.attr('viewBox') && $svg.attr('height') && $svg.attr('width')) {
            $svg.attr('viewBox', '0 0 ' + $svg.attr('height') + ' ' + $svg.attr('width'))

        // Replace image with new SVG

    }, 'xml');

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BRMarketingAuthor Commented:
Thank you Julian Hansen
Julian HansenCommented:
You are welcome.
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