MacOSX: awk using input variable from command line

I have this script which return me a list for selection with the correct information

#!/bin/bash
choices=('Cancel Restore')
choices+=('Delete Older Instances')
choices+=($(aws rds describe-db-snapshots --db-instance-identifier rdsinstance | awk -F'"' '/"DBSnapshotIdentifier": "testvar",/ { print $4 }'))

select choice in "${choices[@]}"; do
...

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however, I want to dynamically replace the tesvar by a variable pushed from the command line

I'm trying the following:

> /location/mybash.sh testvar

#!/bin/bash

variable=$1

choices=('Cancel Restore')
choices+=('Delete Older Instances')

variable=$1
choices+=($(aws rds describe-db-snapshots --db-instance-identifier rdsinstance | awk -v var="$variable" -F'"' '/"DBSnapshotIdentifier": "var",/ { print $4 }'))

select choice in "${choices[@]}"; do
...

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but is not working, I have tried several combinations but without success.
the idea is to filter the below result into a selection list only when the line matches "DBSnapshotIdentifier": "testvar",

{
    "DBSnapshots": [
        {
            "DBSnapshotIdentifier": "testvar",
            "DBInstanceIdentifier": "rdsinstance",
            "SnapshotCreateTime": "2018-05-23T14:32:50.955Z",
            "Engine": "sqlserver-ex",
            "Status": "available",
            "EngineVersion": "11.00.2100.60.v1",
            "SnapshotType": "manual",
            "DBSnapshotArn": "arn:aws:rds:xxxxxxxxxxxxxxxxxx:snapshot: testvar",
        }
    ]
}

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If I use the testvar in the script, I will obtain a choice testvar (the name of the instance) if I try to pass it from the command line, it will not work.

how can I filter the value using an input?