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XSLT 2.0 match attribute of parent to attribute somewhere else

I have some XML data that looks something like this:

<A>
    <B>
        <C href="#hello"/>
    </B>
    ...
    <X id="hello">
        <Y>
        ...

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I'm running an XSLT 2.0 transformation, and I'm on node <Y>. I know there's a parent node <X> above me with an id= attribute, and I suspect there's a section <B> above which has a bunch of child nodes, not necessarily <C> nodes, they may be anything, but they may have an href= attribute that points to the <X id=...> above me.

I now want to test if the id= above me matches any href= in section <B> above. (To make it simple there's only one level below <B>.)

[Earlier when I was on node <X>, I was able to write the following test:]

<xsl:when test="/A/B/*[./@href = current()/concat('#',@id)]

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Pretty close to what I now need, except I need to replace current() with parent(), or parent::, and that's where I'm losing the syntax.

Gertone (Geert Bormans)

you need the current() to maintain your current context
Try
<xsl:when test="/A/B/*[./@href = current()/parent::*/concat('#',@id)]">

but I would use a key

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Gertone (Geert Bormans)

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manoj kumar

NodeList nodelist=doc.geyElementByTagName(A);
for(int i=0;i<nodelist.getLenght();i++)
{
Node node=nodelist.item(i);
NodeList nl=node.getchildNode();
for(int j=0;j<nl.getlenght();j++)
{
Node nodes=nl.item(j);
if(nodes.getnodename().equals("B")
{
//do Operation for B
}
if(nodes.getchildnode().equals("X))
{
//Do Opration for X
}

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Gertone (Geert Bormans)

@manoj kumar
interesting XSLT 2.0 ;-)

deleyd

ASKER

Works like a charm! Thank you!

Gertone (Geert Bormans)

welcome