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sbornstein2

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Oracle query help

I have a dataset that has parents and children that I am calling branches.  Sample dataset:

Branch   TreeId    Name      ParentId
Root        1            GRP A       NULL
Root        2            SET A1      1
Child       6            SET A1B    2
Child       7            SET A1C    2

I then have a TreeId parameter that I need to pull from that level down to the children.  This set will not go higher than a Root record where ParentId IS NULL.  So what I am trying to do is let's say I pass in TreeId 1 in this case I would want the whole set back.   Essentially any ParentId = Null can have additional roots under it.   If I pass treeid = 2 I would want records 2,6 and 7.   If I pass treeid 6 or 7 I would just want that record.

I would want to start with the NULL ParentId if it is null then work down based on the treeid passed in.
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Avatar of slightwv (䄆 Netminder)
slightwv (䄆 Netminder)

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That looks close.  I think you need that last line to be:
start with treeid = 1;
It's more than close...

The question seeks a method that will accept different parameters to produce different results.
The method provided by slightwv is correct; One can use a variety of where clauses and get the expected result of each:

select *
from table1
connect by prior treeid = parentid
start with parentid is null
;

| BRANCH | TREEID |    NAME | PARENTID |
|--------|--------|---------|----------|
|   Root |      1 |   GRP A |   (null) |
|   Root |      2 |  SET A1 |        1 |
|  Child |      6 | SET A1B |        2 |
|  Child |      7 | SET A1C |        2 |


-- pass in TreeId 1, want the whole set back.  
select *
from table1
connect by prior treeid = parentid
start with treeid = 1
;

| BRANCH | TREEID |    NAME | PARENTID |
|--------|--------|---------|----------|
|   Root |      1 |   GRP A |   (null) |
|   Root |      2 |  SET A1 |        1 |
|  Child |      6 | SET A1B |        2 |
|  Child |      7 | SET A1C |        2 |


-- pass treeid = 2, want records 2,6 and 7
select *
from table1
connect by prior treeid = parentid
start with treeid = 2
;

| BRANCH | TREEID |    NAME | PARENTID |
|--------|--------|---------|----------|
|   Root |      2 |  SET A1 |        1 |
|  Child |      6 | SET A1B |        2 |
|  Child |      7 | SET A1C |        2 |

-- pass treeid = 6, want record 6
select *
from table1
connect by prior treeid = parentid
start with treeid = 6
;

| BRANCH | TREEID |    NAME | PARENTID |
|--------|--------|---------|----------|
|  Child |      6 | SET A1B |        2 |

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also see http://sqlfiddle.com/#!4/d2a7fa/1
I agree that with this small data set, either of these lines will return the same results (and quickly):
start with parentid is null;
or
start with treeid = 1;

But in most production systems, the performance difference between these two can be *VERY* different!  The "is null" option will force a full-table scan.  If the table has a million records, that will take a while.  The "treeid = 1" option will use an index (assuming the table has an index on this column).  That will be *MUCH* faster if the table has more than a couple thousand rows.
Avatar of slightwv (䄆 Netminder)
slightwv (䄆 Netminder)

>>I think you need that last line to be:  start with treeid = 1;

Paul is correct.  6 was just my last test case in the original requirement:
If I pass treeid = 2 I would want records 2,6 and 7.   If I pass treeid 6 or 7 I would just want that record.

I didn't post all combinations.  I thought it was sort of a given.

>>these lines will return the same results (and quickly): start with parentid is null;  or start with treeid = 1;

I get no rows is I use 'is null'.
Parentid is null
Will return rows

Treeid is null
Would not return rows from the sample
Sorry.  I didn't read the actual column involved.  :(