asked on

LOOK FOR VALUE, THEN TAKE NEXT 12 COLUMNS AND SUM THEM

need a formula to find the column where an array crosses a certain threshold

so need to find the column number where that happens

threshold is 19,000 , looking for the first time an array crosses that mark

note- an array is between columns H-CA

then i need to sum the NEXt twelve columns of data.

so for example, if COL M has 17,500 AND col N has 19,400, and this was first time we crossed 19,000 (ie it didnt happen in colmns A-L, then i need to sum columns O-Z

need to do this across rows 7-480

abbas abdulla

Hi,

Check entering below function using keyboard combinations Ctrl+Shift+Enter

=AVERAGE(INDIRECT(ADDRESS(7,SMALL(IF(H7:CA700>=19000,COLUMN(H7:CA700),),1))& ":"&ADDRESS(700,SMALL(IF(H7:CA700>=19000,COLUMN(H7:CA700),),1)+11),1))

finnstone

ASKER

sorry did not work

#value

abbas abdulla

Unfortunately I have no access now to excel but same function is working in google sheets. Check this link https://docs.google.com/spreadsheets/d/11OqfWNeAo99TPlqHO3kzK2CSqkl3Ee98JNscRh83ROY

I will test function using excel tomorrow if you didn't get solution. Can you please post dummy data sample that shows what you are trying to achieve?

Subodh Tiwari (Neeraj)

So if a value greater than 19000 (say 19400) is found in column N, do you want to sum the values in the range O7:Z480?
If so, try this Array Formula which requires confirmation with Ctrl+Shift+Enter instead of Enter alone.

=SUM(OFFSET(INDIRECT(ADDRESS(7,COLUMN(INDEX(H7:CA480,SMALL(IF(H7:CA480>19000,ROW(H7:CA480)-ROW(H7)+1),1),SMALL(IF(H7:CA480>19000,COLUMN(H7:CA7)-COLUMN(H7)+1),1))))),,1,474,12))

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finnstone

ASKER

can you change this ti just sum the row that it is working on please?

also can you create one that does the prior 12 columns before 19000. thanks!!!!

Subodh Tiwari (Neeraj)

I have logged off as it is 2 AM here and on mobile right now. I will check it tomorrow.
Btw do you mean if 19400 is found in N15, you want to sum only O15:Z15?

finnstone

ASKER

YES O:Z

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Subodh Tiwari (Neeraj)

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finnstone

ASKER

THANKS. I am starting a new question for you