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 How do I in Oracle SQL check if the field contain text with length 18 & contain [a..z,A..Z,0..9] chars only

Jamil MuammarAsked:
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Alexander Eßer [Alex140181]Software DeveloperCommented:
create table test(id number, str varchar2(50));

insert into test values(1,  '123456789123456789');
insert into test values(2,  'abcdefghi123456789');
insert into test values(3,  'aA34567891234567zZ');
insert into test values(4,  '12345678912345678910');
insert into test values(5,  '.?3456789123456789');
insert into test values(6,  '_$3456789123456789');
insert into test values(7,  'xx123456789123456789');
insert into test values(8,  'AA123456789123456789');
insert into test values(9,  'foo 123456789123456789');
insert into test values(10, '  3456789123456789');

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select a.str,
  from test a
 where regexp_like(a.str, '[[:alnum:]]{18}')
   and length(a.str) = 18;

select a.str,
       regexp_instr(a.str, '[[:alnum:]]{18}')
  from test a
 where length(a.str) = 18;

Open in new window!4/30060/11
slightwv (䄆 Netminder) Commented:
Slight modification that removes the length check:
select a.str,
  from test a
 where regexp_like(a.str, '^[[:alnum:]]{18}$');

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