C++ STL list::sort(Compare Comp) compile error: "no matching member function for call to 'sort' ... where compare function has been templatized.

Question is related to C++ STL list::sort(Compare) where Compare is now a template.

I am looking for the correct syntax to override the list::sort(Compare) definition to work with list<pair<int, T> > definition.

//-The Compare Function

template<typename W>
bool weightsort(const pair<int, W> &node1, const pair<int, W> &node2)
{
    return (node1.second <= node2.second);
}


//- Abbreviated class definition containing  STL list definition and call to sort

template<typename T>
class Graph {
    ...
    vector<T> shortest_reach(int startId, T sigWeight) {
        ...
        list<pair<int, T> >                                       frontier;   //-Nodes currently on the Queue to be Explored.
        typename list<pair<int, T> >::iterator      fit;
        ...
            frontier.sort(weightsort);
        ...
    }
    ....
};


$ c++ program.cpp

error: no matching member function for call to 'sort'
            frontier.sort(weightsort);
            ~~~~~~~~~^~~~

usr/include/c++/v1/list:1059:14: note: candidate template ignored:
      couldn't infer template argument '_Comp'
        void sort(_Comp __comp);
             ^
/usr/include/c++/v1/list:1056:10: note: candidate function not viable:
      requires 0 arguments, but 1 was provided
    void sort();
         ^
J FAsked:
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Fabrice LambertFabrice LambertCommented:
Hi,

start by remove this horrible "using namespace std;" that you're hiding, and fully qualify your data types. I suspect some ambiguities.
You're full class definition and dependencies will probably help also.
0
J FAuthor Commented:
I did as you suggested and I still have the same compiler errors.
bool weightsort()  worked prior to converting it to a template.
0
J FAuthor Commented:
The call to frontier.sort(weightsort) was missing the template parameter.
The solution is to call  frontier.sort(weightsort<T>) .
1

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