troubleshooting Question

Update page content cURL and ajax without page refresh

Avatar of Vincenzo Vecchio
Vincenzo Vecchio asked on
6 Comments2 Solutions681 ViewsLast Modified:

I've a form to send a ajax request which return a json object from a cURL request. I use the form to query the API using the start and and the end date. I've managed to show the datas returned into a table as suggested in this post
Now my problem is every time a make a new request from my form a new table is shown to the form page just after the table I've obtained with the previous request, is there any way to show only one table, so at every form request the previus data is replaced with the new data?

This is my javascript code:
    $(document).ready(function() {

      // Function to create table layout
      function createTable(data) {
        var table = document.createElement('table');
        var header = table.insertRow();

        for(var h in data[0]) {
          var th = document.createElement('th');
          th.innerHTML = h;

        data.forEach(function(item) {
          var row = table.insertRow();
          for(var v in item) {
            var cell = row.insertCell();
            if (Array.isArray(item[v])) {
              var subtable = createTable(item[v]);
            else {
              cell.innerHTML = item[v];

        return table;

      // Initialize air datepicker plugin

      // Store form into variable
      var form= $("#requestForm");

      // Actions when form is submitted
      $('#submitForm').click(function(e) {

        // Ajax request

          type: "POST",
          url: form.attr("action"),
          data: form.serialize(),
          success: function(result){

            // Show the table container

            // Convert reponse into JSON
            datas = JSON.parse(result);
            // Get nome condominio and show it
            // Get indirizzo condomino and show it
            // Put datas into table using the function createTable
            var table = createTable(datas.condomini[0].ricevute);
            // Show table 



          error: function(error, status, xhr) {
            console.log(error, status, xhr);

        }); // Fine ajax
       e.preventDefault(); // Prevent form to be sent

      }); // fine submit form
    }); // fine document ready

This is my html code
<form id="requestForm" action="../km-client-controllers/km-ctrl-client-ricevute.php" method="POST">
              <div class="form-row">
                <div class="form-group col-md-3">
                  <label for="startDate">Data di inizio ricevuta</label>
                  <input type="text" class="form-control air-datepicker" data-date-format="dd/mm/yyyy" data-language='en' placeholder="Data di inizio" id="startDate" name="startDate">
                <div class="form-group col-md-3">
                  <label for="endDate">Data di fine ricevuta</label>
                  <input type="text" class="form-control air-datepicker" data-date-format="dd/mm/yyyy" data-language='en' placeholder="Data di fine" id="endDate" name="endDate">

              <button type="submit" class="btn btn-primary" id="submitForm" >Mostra ricevute</button>

          <div class="container-fluid" id="tableContainer" style="display: none" >
            <h2 class="text-center"><div id="nome_condominio"></div></h2>
            <h4 class="text-center"><div id="indirizzo_condominio"></div></h4>
           <div id="table"></div>

And this is my php code

	$startDate = $_POST['startDate'];
	$endDate = $_POST['endDate'];

	$dates= array(

		'd_inizio' => $startDate,
		'd_fine' => $endDate

		$url = "";

		if (!isset($_SESSION['cookiefile'])) {
		    die("no cookie file");

	$cookie = "../../km-controllers/" . $_SESSION['cookiefile'];

	$ch = curl_init ($url);
	curl_setopt($ch, CURLOPT_POST, 1);
	curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($dates));
	curl_setopt ($ch, CURLOPT_COOKIEFILE, $cookie); 
	curl_setopt ($ch, CURLOPT_RETURNTRANSFER, true);
	$output = curl_exec ($ch);


	echo $output;
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