Extract only group and owner name in the ls -l output
Hi Team,
I want to extract the group name and owner name from the ls -l command output , below is the command which I have written , not able to get the output .
ls -l | sed -n '/^-/s/^-.* [0-9] \([[:alpha:]] [[:alpha:]]\).*/\1/p'
-rw-r--r--. 1 root root 0 Nov 12 23:53 abc.txt
-rw-------. 1 root root 2629 Nov 11 01:17 anaconda-ks.cfg
-rw-r--r--. 1 root root 139 Nov 12 22:13 CALNOV
-rw-r--r--. 1 root root 0 Nov 12 23:54 cc
-rw-r--r--. 1 root root 0 Nov 13 00:05 $file
-rw-r--r--. 1 root root 48 Nov 12 21:56 filename
-rw-r--r--. 1 root root 41955 Nov 11 01:17 install.log
-rw-r--r--. 1 root root 9154 Nov 11 01:11 install.log.syslog
-rw-r--r--. 1 root root 2682 Nov 12 22:42 logdata
-rw-r--r--. 1 root root 1054 Nov 12 21:58 LOGFILENAME
-rw-r--r--. 1 root root 81 Nov 13 07:22 meals
-rw-r--r--. 1 root root 82 Nov 13 05:20 names
-rw-r--r--. 1 root root 79 Nov 13 07:27 newnames
-rw-r--r--. 1 root root 139 Nov 12 22:09 novcal
-rw-r--r--. 1 root root 0 Nov 12 23:52 test
-rw-r--r--. 1 root root 13 Nov 10 21:25 test1
-rw-r--r--. 1 root root 0 Nov 12 23:52 test2
i want to show only root root in the output for all the files
I want to extract the group name and owner name from the ls -l command output , below is the command which I have written , not able to get the output .
ls -l | sed -n '/^-/s/^-.* [0-9] \([[:alpha:]] [[:alpha:]]\).*/\1/p'
-rw-r--r--. 1 root root 0 Nov 12 23:53 abc.txt
-rw-------. 1 root root 2629 Nov 11 01:17 anaconda-ks.cfg
-rw-r--r--. 1 root root 139 Nov 12 22:13 CALNOV
-rw-r--r--. 1 root root 0 Nov 12 23:54 cc
-rw-r--r--. 1 root root 0 Nov 13 00:05 $file
-rw-r--r--. 1 root root 48 Nov 12 21:56 filename
-rw-r--r--. 1 root root 41955 Nov 11 01:17 install.log
-rw-r--r--. 1 root root 9154 Nov 11 01:11 install.log.syslog
-rw-r--r--. 1 root root 2682 Nov 12 22:42 logdata
-rw-r--r--. 1 root root 1054 Nov 12 21:58 LOGFILENAME
-rw-r--r--. 1 root root 81 Nov 13 07:22 meals
-rw-r--r--. 1 root root 82 Nov 13 05:20 names
-rw-r--r--. 1 root root 79 Nov 13 07:27 newnames
-rw-r--r--. 1 root root 139 Nov 12 22:09 novcal
-rw-r--r--. 1 root root 0 Nov 12 23:52 test
-rw-r--r--. 1 root root 13 Nov 10 21:25 test1
-rw-r--r--. 1 root root 0 Nov 12 23:52 test2
i want to show only root root in the output for all the files
ASKER
Hi ,
I want to try it using sed command only. Can help where Iam going wrong in the regular expression.
I want to try it using sed command only. Can help where Iam going wrong in the regular expression.
ASKER CERTIFIED SOLUTION
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Can you try this:
ls -l | sed -n 's/\(^-.\{9\}\)\( *\)\([0-9]\) \([a-z][a-z]*\)\( *\)\([a-z][a-z]*\).*/\4 \6/p'
One thing that is wrong with your pattern is that you have one space between your 2 alpha's where you sample output has 2 spaces in between.
ls -l | sed -n 's/\(^-.\{9\}\)\( *\)\([0-9]\) \([a-z][a-z]*\)\( *\)\([a-z][a-z]*\).*/\4 \6/p'
One thing that is wrong with your pattern is that you have one space between your 2 alpha's where you sample output has 2 spaces in between.
SOLUTION
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find . -type d -exec ls -ld {} \; | awk '{print $3,$9}' | grep -v oasitqtc
It should give you desired output
However better code will be with egrep as states below :
find . -type d -exec ls -ld {} \; | awk '{print $3,$9}' | egrep -v "^oasitqtc"
Try both :)
Hope this helps