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Python: Running sudo

Hi ...

Trying running a python script that calls a bash script as sudo. to get all the standard input/output using the below:

sas_cmd = ['sudo', 'apacheart']
proc = subprocess.Popen(sas_cmd, shell=True, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE)

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it is not calling the script at all ....
But, if i do the following:

proc = subprocess.Popen(['sudo','/usr/bin/apacheart'])

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It calls the script.
Can someone please help to get the std/stout.
Thanks

dfke

Hi,

something like:

from subprocess import Popen, PIPE

p = Popen(['sudo', '/usr/bin/apacheart'], stdin=PIPE, stdout=PIPE, stderr=PIPE)
output, err = p.communicate(b"input data that is passed to subprocess' stdin")
rc = p.returncode

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Cheers

NetRock6

ASKER

@dfke,
Thanks for your help.
It calls the script but i do not see any stdout.
Any idea why?

Thanks

Anthony Garcia

Did you print the output variable and see nothing?

NetRock6

ASKER

I print 'rc' and get 0 ...

Anthony Garcia

rc contains the return code which is 0 when the command is successful. You want to print the variable named output if you are using the code that dfke posted above.

NetRock6

ASKER

You mean:
print (output)

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dfke

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NetRock6

ASKER

Great dfke. Thanks.
This is what I exactly was looking for. Is there a way to open a shell and direct the outputs in that shell.
Thank you again for your great help.
Cheers