awk command issue
zgrep 'MobileDevice' xyz.log.20181121.gz|grep 'USER123'| awk '$0>= "2018-Nov-21 00:01" && $0<="2018-Nov-21 23:59"' | awk -F '|' '$24>300 {print}'
above grep printing all the columns successfully satisfying abov condition of
$24>300
Now i need to filter above query based on the state like Florida which is printing in 23rd column i.e $23
zgrep 'MobileDevice' xyz.log.20181121.gz|grep 'USER123'| awk '$0>= "2018-Nov-21 00:01" && $0<="2018-Nov-21 23:59"' | awk -F '|' '$23=FLORIDA {print}'
above query not working
how to check String equality in AWK
Please advise
above grep printing all the columns successfully satisfying abov condition of
$24>300
Now i need to filter above query based on the state like Florida which is printing in 23rd column i.e $23
zgrep 'MobileDevice' xyz.log.20181121.gz|grep 'USER123'| awk '$0>= "2018-Nov-21 00:01" && $0<="2018-Nov-21 23:59"' | awk -F '|' '$23=FLORIDA {print}'
above query not working
how to check String equality in AWK
Please advise
= is assignment / == is comparing for equality
FLORIDA is a variable...
so try $23 == "FLORIDA" as condition.
FLORIDA is a variable...
so try $23 == "FLORIDA" as condition.
if i have to give both together how i do it?
zgrep 'MobileDevice' xyz.log.20181121.gz|grep 'USER123'| awk '$0>= "2018-Nov-21 00:01" && $0<="2018-Nov-21 23:59"' | awk -F '|' '$24>300 | awk -F '|' '$17==300 {print}'
above giving as below
>
then expecting something
i am confused where to start ' and where to end it '
please advise
zgrep 'MobileDevice' xyz.log.20181121.gz|grep 'USER123'| awk '$0>= "2018-Nov-21 00:01" && $0<="2018-Nov-21 23:59"' | awk -F '|' '$24>300 | awk -F '|' '$17==300 {print}'
above giving as below
>
then expecting something
i am confused where to start ' and where to end it '
please advise
so try $23 == "FLORIDA" as condition.did not work
please advise
any sample commands like this in any link or resource or book?
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