min query issues

SELECT  COUNT (*) from SALARIES  WHERE salary>(SELECT  MIN (Salary ) from SALARIES )

somet reason above i am getting wrong count
instead of 6 i am getting 15

please advise on how to optimize and make it better
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Raja Jegan RSQL Server DBA & Architect, EE Solution GuideCommented:
>> instead of 6 i am getting 15

Query seems correct and no need for further optimization..
Can you kindly explain with some test data to show why it should return 6 instead of 15 so that we can help modify the query accordingly.

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Geert GOracle dbaCommented:
min(salary) is 1 record (or more records with same salary)

it's returning everything except the first record
awking00Information Technology SpecialistCommented:
Please post the salary values that you queried.
Jim HornSQL Server Data DudeCommented:
Agree with the above experts.  Keep in mind that experts here cannot connect to your data sources and run queries, so we are entirely dependent on what you provide us in the question to provide an answer, and that includes sample data.

Otherwise why 15 is being returned instead of 6 ... no idea.

Off of top of my head though (as Geert states above) if you are filtering by the minimum value of Salary then I would expect the return set to have the same number of rows in the table itself minus those rows where the salary = minimum value, and minus any NULLs.
slightwv (䄆 Netminder) Commented:
Also agree that we cannot help without seeing the data.

As I a posted in your MAX question:  If you think you need to query the table twice, rethink it.

This should return the same results and only access the table once:
SELECT  COUNT (*) from
	select salary, min(salary) over () min_salary from tab1
) salaries
WHERE salary> min_salary

Open in new window

Without the data you have, I cannot say if it will return 6 or 15 rows.
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Query Syntax

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