Solve the display duplicate in the table rows

I want make a display Candy name only display icon tick in the column Candy without duplicate in column melvin and angel . But right now my data is duplicate over in every name column .
question1.JPGThis is my table display right now

      <div class="card mb-3">
        <div class="card-header">
          <i class="fa fa-table"></i> Calendar</div>
        <div class="card-body">
          <div class="table-responsive">
            <table class="table table-bordered" id="dataTable" width="100%" cellspacing="0">
			  $namearr = array(); 
			  $sql="select * from admin_staff";
			  $result3= mysqli_query($DBcon,$sql);
			  while ($row3= $result3->fetch_array()){ 
			  <th><?php echo $row3['name']; }?></th>
				$open_time = strtotime("9:00");
				$close_time = strtotime("21:00");
			  for($i=$open_time; $i<$close_time; $i+=3600){
			  <td><?php echo date("l - H:i",$i); ?></td>

			  $sql_count="select count(*) as counter from admin_staff";
			  $result_count= mysqli_query($DBcon,$sql_count);
			  $rowcount= mysqli_fetch_assoc($result_count);
				$new_time= date("H:i:s",$i);
			  	$sql= "select * from admin_calendar where time='$new_time'";
				$result4= mysqli_query($DBcon,$sql);
				$row4= mysqli_fetch_assoc($result4);												
				echo $row4['user'];
			  <?php } }?>
        <div class="card-footer small text-muted"></div>

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admin_calendar tableThis is admin calendar table

admin_staff tableThis is admin staff table
Yong Scott Asked:
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Raja Jegan RSQL Server DBA & Architect, EE Solution GuideCommented:
select * from admin_staff

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Instead of selecting the records like this, you can apply the PIVOT logic and then use the PIVOT query to select the data converted to the required format and then easily display it in your PHP page..
More info on how to PIVOT data with an example here..
sorry, i'm using a keyboard that has no parenthesis so you'll need to convert < > to regular brackets

if < user = "melvin" , "yes" ,"" > as melvin,
if < user = "candy" , "yes" ,"" > as candy,
from calendar

the equivalent in php will work as well by comparing your $row3 with the current user.

whichever way you pick, there is no reason to run more than a single query to display the whole thing.
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