Create custom Replace function

Hi Experts,

I am looking to create a function that will accept a string and only return the alpha/numeric values, except for dashes all special characters should get stripped out.

So instead of having to use the following
fieldName = Left(Replace(Replace(Replace(Mid(ColumnName, 2, Len(ColumnName) - 2), " ", ""), "&", ""), "+", ""), 32)

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I can call my function something like

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P.S. If possible, would prefer to have the 2nd variable of the function (the one holding the dash) capable of managing more than one character as an exception, so I can send "_,-,' ') and all 3 of them would be considered valid characters, not getting stripped out.

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Daniel PineaultPresident / Owner CARDA Consultants Inc.Commented:
RegEx might be a good option for this.

Jim Dettman (Microsoft MVP/ EE MVE)President / OwnerCommented:
Here's a good article on EE about regex:

 beyond that, there is a lot of generic "find and replace" code floating around.    But this seems specific enough for you to write your own.

 It's simple enough....just loop through the string and dump anything you don't want.   Generally done with an In and out string, the latter of which you build up as you read the "in" string.

Zakaria AcharkiAnalyst DeveloperCommented:
You could use regex, this one will help you :


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You could add as many special characters you want to ignore, that you will pass in the second argument like :

"[^A-Za-z\d" & ingoredChars & "]"

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You just need to pass the ingoredChars together like "_-,'" in the second argument.

The whole function code could be something like :

Private Function MyReplace(ByVal strVar As String, ByVal ingoredChars As String) As String
    Set objRegExp_1 = CreateObject("vbscript.regexp")
    objRegExp_1.Global = True
    objRegExp_1.IgnoreCase = True
    objRegExp_1.Pattern = "[^A-Za-z\d" & ingoredChars & "]"
    MsgBox ( objRegExp_1.Replace(strVar, "") )
End Function

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And you could call it like :


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Not tested yet.

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bfuchsAuthor Commented:

Middle of testing yours...seems to work-:)

Can you explain why do I get into the debug line?
fieldName = Left(Replace(Replace(Replace(Replace(Mid(ColumnName, 2, Len(ColumnName) - 2), " ", ""), "&", ""), "+", ""), "-", ""), 32)
                        If fieldName <> Left(MyReplace(Mid(ColumnName, 2, Len(ColumnName) - 2), "_"), 32) Then
                            Debug.Print fieldName
                        End If

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See attached.

bfuchsAuthor Commented:
Thanks to all participants!
Zakaria AcharkiAnalyst DeveloperCommented:
You're welcome @bfuchs, glad to help.
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