troubleshooting Question

Why this perl code about eval not work

Avatar of Chunhua Du
Chunhua Du asked on
29 Comments6 Solutions196 ViewsLast Modified:
Code is here:

my $a1 = ‘a1_v’;
my $c1;
my $varName;

my $code = qq(
      \$varName = ‘a1’;
      eval(‘\$c1 = \$\$varName;’);


# I hope this line print a1_v, but print nothing
print “$c1\n”;
nociSoftware Engineer
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