How to get distinct list when all records are true

Does this not work?

SELECT DISTINCT Id, Field1, Field2, Field3
FROM YourTable
WHERE Field1 = 'Y' OR Field2='Y' OR FIeld3='Y'

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or would it be something like this:

DECLARE @data TABLE (
	id INT,
	field1 CHAR(1),
	field2 CHAR(1),
	field3 CHAR(1)
)

INSERT INTO @data ( id, field1, field2, field3 )
VALUES 
(1, 'Y', 'N', 'N' ),
(1, 'N', 'N', 'N' ),
(2, 'Y', 'N', 'Y' ),
(2, 'Y', 'N', 'N' ),
(3, 'N', 'Y', 'N' ),
(3, 'N', 'Y', 'N' ),
(3, 'N', 'Y', 'N' )


--SELECT * FROM @data

; WITH cte
AS (
	SELECT A.id, COUNT(*) AS NbRows
	, (SELECT COUNT(*) FROM @data WHERE id = A.id AND field1 = 'Y') AS F1
	, (SELECT COUNT(*) FROM @data WHERE id = A.id AND field2 = 'Y') AS F2
	, (SELECT COUNT(*) FROM @data WHERE id = A.id AND field3 = 'Y') AS F3
	FROM @data AS A
	GROUP BY A.id
)

SELECT cte.id
FROM cte
WHERE cte.NbRows = cte.F1 OR cte.NbRows = cte.F2 OR cte.NbRows = cte.F3


DELETE FROM @data

INSERT INTO @data ( id, field1, field2, field3 )
VALUES 
(1, 'Y', 'N', 'N' ),
(2, 'Y', 'N', 'Y' ),
(2, 'Y', 'N', 'N' ),
(3, 'N', 'Y', 'N' ),
(3, 'N', 'Y', 'N' ),
(3, 'N', 'Y', 'N' )


--SELECT * FROM @data

; WITH cte
AS (
	SELECT A.id, COUNT(*) AS NbRows
	, (SELECT COUNT(*) FROM @data WHERE id = A.id AND field1 = 'Y') AS F1
	, (SELECT COUNT(*) FROM @data WHERE id = A.id AND field2 = 'Y') AS F2
	, (SELECT COUNT(*) FROM @data WHERE id = A.id AND field3 = 'Y') AS F3
	FROM @data AS A
	GROUP BY A.id
)

SELECT cte.id
FROM cte
WHERE cte.NbRows = cte.F1 OR cte.NbRows = cte.F2 OR cte.NbRows = cte.F3

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SELECT id
FROM @data
GROUP BY id
HAVING
      MIN(CASE WHEN field1 = 'Y' THEN 1 ELSE 0 END) = 1 OR
      MIN(CASE WHEN field2 = 'Y' THEN 1 ELSE 0 END) = 1 OR
      MIN(CASE WHEN field3 = 'Y' THEN 1 ELSE 0 END) = 1

I believe Scott's approach will efficiently solve the question as asked.

I just wanted to show an alternative that would also allow determination of which column has all 'Y's

It starts by "unpivoting" the data (but not by using the "unpivot" command, I find the following to be simpler syntax for that). Once that is complete it sis is just a group by query to complete the task.

CREATE TABLE mytable(
   Id     INTEGER  NOT NULL
  ,Field1 VARCHAR(4) NOT NULL
  ,Field2 VARCHAR(2) NOT NULL
  ,Field3 VARCHAR(2) NOT NULL
);
INSERT INTO mytable(Id,Field1,Field2,Field3) VALUES (1,'Y','N','N');
INSERT INTO mytable(Id,Field1,Field2,Field3) VALUES (1,'N','N','N');
INSERT INTO mytable(Id,Field1,Field2,Field3) VALUES (2,'Y','N','Y');
INSERT INTO mytable(Id,Field1,Field2,Field3) VALUES (2,'Y','N','N');
INSERT INTO mytable(Id,Field1,Field2,Field3) VALUES (3,'N','Y','N');
INSERT INTO mytable(Id,Field1,Field2,Field3) VALUES (3,'N','Y','N');
INSERT INTO mytable(Id,Field1,Field2,Field3) VALUES (3,'N','Y','N');

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select ca.id, ca.all_y
from mytable
cross apply (
    values
      (id, 'field1', field1)
    , (id, 'field2', field2)
    , (id, 'field3', field3)
    ) ca (id, all_y, fieldval)
group by  ca.id, ca.all_y
having min(fieldval) = max(fieldval) and max(fieldval) = 'Y'
;

+-----+--------+
|  id | all_y  |
+-----+--------+
|   2 | field1 |
|   3 | field2 |
+-----+--------+

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hello i would like to recommend a differend possibility.
in case of most records are valid, it's a good idea to search for records which are not matching. In addition then you have a cobination of AND which is faster then OR.

so may be:

SELECT DISTINCT ID from mytable where ID not in (
SELECT ID from mytable where field1 = 'N' AND field2 = 'N' AND field3 = 'N'
)

please check finaly execution plan to see what is your optimal solution.
Good luck