Get the Time of Day from a Field that is all seconds.

Hope somebody can help with this one:
I have a field that is defined as having all seconds, how can I get the Time of Day out of that field.
field is 908022961 (seconds)
 to_date('19900101','yyyymmdd') + "starttime"/86400 as startDate,  (From SQL---but would like to use Crystal to get the Time of Day).
it will convert to this date 2018-10-10 with the above statement.  

Date is 10/10/2018,   but I need to find the time of day for this.  
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KimputerIT ManagerCommented:
DateAdd(“s”, 908022961, “01/01/1990”) 

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Try this one

Time(DateAdd('s', 908022961, Date(1900,01,01)))

tambrosiAuthor Commented:
Thanks for the input that will get me the time of day which is what I asked for.  Much appreciated.

But found out yesterday I need the mmddccyy also.  
   Found out I will have to get the mmddccyy from that string also,  is that doable also.  

Vendor defined the field as "initial start time in seconds since 1/1/1990'

Any help would be appreciated.

CStr(DateAdd('s', 908022961, Date(1900,01,01)), 'mmddyyyy')


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tambrosiAuthor Commented:
thanks for all of the input.   It is greatly appreciated.!!!!
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