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EIGRP Best Path Selection

EIGRP Best Path Selection

Assuming R1 has 2 paths to reach route 11.11.11.11 behind R4

R1--->R2--->R3----R4
R1---->R5--->R6----R4

The bandwidth : R1 to R2  :1.544kbps  R2 to R3: 128Kbps  R3 to R4 : 1.544kbps

The bandwidth : R1 to R5  :256Kbps  R5 to R6: 256Kbps  R6 to R4 : 256 Kbps

Which path R1 will choose to reach R4 ?

Thank you
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Benjamin Van Ditmars
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Assuming  everything else is equal except for the bandwidth  as mentioned above then  if I understand your statement the path R1-R5-R6-R4  is Selected.

if so then Why ?
The path is calculated through the topology and the throughput in the first line R1-R2-R3-R4 is the 128kb connection.
so the total K value of that road is higher then the R2-R5-R5-R4 road.
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ASKER

by the way 1.544kbps I meant 1.544Mbps

So the Throughput via : R1--->R2--->R3----R4   is higher  even with  one link that has 128 Kbps
So why would it take the path :  R1---->R5--->R6----R4 instead of  R1--->R2--->R3----R4
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Thanks