How to use $_SESSION variables in PHP between web pages.
Need to understand $_SESSION variables in php (2 weeks into wrestling with php for the first time)
Trying to implement Google login to a student survey, accessed via gmail. Prior version worked with an LDAP login, using the variable username.
The google login code returns $userid. Then I was told to use $_SESSION['valid_user'], so I tried this: $_SESSION['valid_user'] = $userid;. But haven't been able to get this to work.
Mainly I need to populate $username with $_SESSION['valid_user'] and use that for several MySQL statements.
For example - current MySQL code
- $query = "SELECT * FROM sum_training WHERE student_id = ' ".$username." ' ";
- $query = "INSERT INTO sum_training (student_id_with_tng_cycle
I ended up with this for username: $_SESSION[2a, where it should have been sjones2a
Original code: sessionStorage.setItem("st
Also, having a hard time debugging this, so if you have a good php debugging link at your fingertips, that will really help.
Trying to implement Google login to a student survey, accessed via gmail. Prior version worked with an LDAP login, using the variable username.
The google login code returns $userid. Then I was told to use $_SESSION['valid_user'], so I tried this: $_SESSION['valid_user'] = $userid;. But haven't been able to get this to work.
Mainly I need to populate $username with $_SESSION['valid_user'] and use that for several MySQL statements.
For example - current MySQL code
- $query = "SELECT * FROM sum_training WHERE student_id = ' ".$username." ' ";
- $query = "INSERT INTO sum_training (student_id_with_tng_cycle
I ended up with this for username: $_SESSION[2a, where it should have been sjones2a
Original code: sessionStorage.setItem("st
Also, having a hard time debugging this, so if you have a good php debugging link at your fingertips, that will really help.
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SOLUTION
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Regarding the debugging part of your question.
When you're developing code, ALWAYS turn on error_reporting. Without it, your code becomes a black box and will often fail without ever telling you why. You can do that by simply adding the following to the very top of all your scripts:
Once you've done that, the next best thing to learn when debugging is the var_dump() method. This basically outputs all the information about your data, so in your code, you could do something very simple like this:
There are more advanced ways of debugging (xdebug / logging for example), but var_dump and error_reporting will get you going in the right direction.
When you're developing code, ALWAYS turn on error_reporting. Without it, your code becomes a black box and will often fail without ever telling you why. You can do that by simply adding the following to the very top of all your scripts:
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);Once you've done that, the next best thing to learn when debugging is the var_dump() method. This basically outputs all the information about your data, so in your code, you could do something very simple like this:
<?php
session_start();
var_dump($_SESSION);There are more advanced ways of debugging (xdebug / logging for example), but var_dump and error_reporting will get you going in the right direction.
ASKER
got it working!!!!!!! Thank youuuuuuu :-)
I'm just taking over this code and learning php on the fly along with putting some WD-40 on my HTML skills.
So the explanation was spot on the money, and the example got me going, then as I was looking around, session_start(); was comment out in all the main files ---- grrrrr..
worked first time too ... bingo.
But good to go, thx
I'm just taking over this code and learning php on the fly along with putting some WD-40 on my HTML skills.
So the explanation was spot on the money, and the example got me going, then as I was looking around, session_start(); was comment out in all the main files ---- grrrrr..
worked first time too ... bingo.
But good to go, thx
ASKER
Chris, just saw your comment, thanks as well - very helpful.
ASKER
hielo - thank you as well!
double checking everything now ...