asked on

process file in a loop

Linux OS, ksh script

I have a shell script and within this shell script there is a line that execute set of commands on a file in a folder. It is something like this

mycommand1 /home/joe/fileFolder xyzd_org1_500.tar.gz
mycommand2
mycommand3
..
..
mycommandn

Now the requirement changed and the folder can have multiple files as follows

xyzd_org1_500.tar.gz
xyzd_org1_503.tar.gz
xyzd_org1_504.tar.gz
xyzd_org1_505.tar.gz

Now I want put all the commands in a function which accepts the file has a parameter, then call the function in a loop for each file (in ascending order), process 500, 503, 504 etc..
If there is a failure in the function, the shell script should exit with an error without processing the next files. How to do this?

Pierre François

Try this:

folder="/home/joe/fileFolder"               # double quotes in case the path to the folder contains a space
files=$(cd "$folder"; ls xyzd_org1_*.tar.gz)
for file in $files ; do
  mycommand1 "$folder" $file || break       # quit the loop if mycommand1 failed
  mycommand2
  mycommand3
  ..
  ..
  mycommandn
done

Open in new window

gs79

ASKER

Is there a way to put list of commands (command 1 to command n) that I need to run to process each file into a function and pass the file name to this function within a for loop?

ASKER CERTIFIED SOLUTION

Pierre François

membership

This solution is only available to members.

To access this solution, you must be a member of Experts Exchange.

Start Free Trial

gs79

ASKER

let me try this and get back to you

gs79

ASKER

Thanks. The programs works