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ConernestoFlag for United States of America

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Access database relationships

I am creating a database with three tables. The names of my tables are One_tbl, States_tbl, and Two_tbl.

One_tbl has a primary field called Acode that is a primary key.
States_tbl has a field called "St" that is a primary key.

I want table Two_tbl to have all records from States_tbl filed "St" and all the records from Acode from my table One_tbl

What I want on table Two:

St           Acode

AK         15(a)
AK          15(c )
AL          15(a)
AL           15(c )


The above is an example of two States AK and AL. How do I do this? Attached is my sample databaseAdjustments.accdb
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John Tsioumpris
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I think you mean Many-To-Many relationship
Check my attachment
Adjustments.accdb
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ASKER

I see that you created a Form. I need in the table name Two_tbl all records from Field  St and next each St the field Acode from the One_tbl.
Just use the comboboxes to populate Two_table
Attached is a revised version of the database. To get what I need, I created a relationship (see relationships in database tools. I then opened One_tbl, expended the first plus sign and copied the 50 St codes. I then opened the next plus sign and copied the 50 St codes. This is how I got my table two to show all the codes that I need see below sample and from attached see table two. Is there a way to do what I did without copying the fifty states into each primary key in table One?

St      Acode      Amount      Percent
AK      15(a)            0.00
AK      15(c )            0.00
AL      15(c )            0.00
AL      15(a)            0.00
Test_Adjustments.accdb
Easy...run this Query
INSERT INTO Two_tbl ( ACode, St )
SELECT One_tbl.ACode, States_tbl.St
FROM One_tbl, States_tbl;

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I entered what you sent in  SQL in a query. When I run the query the records don't get updated. I think I am doing something wrong.
ASKER CERTIFIED SOLUTION
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John Tsioumpris
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Make table code works. Thank you.

Conernesto
Ideally I would like that every new primary key that is added on table One is also added on table two?
Just try it...