Parse, sort and get latest value
Hi Bash experts,
Trying to parse multiple xml files in a directory.
Extract an attribute value from available xml files. e.g liferay-version="20.0.1.5"
sort them and get the greatest value from the identified list. e.g "20.0.1.8" and store them in a variable
Was trying using python, but due to restriction on my work server. couldn't install additional packages, so couldn't use python.
Is it possible using sed/awk/bash or any way please.
file1.txt
file2.txt
file3.txt
file4.txt
Trying to parse multiple xml files in a directory.
Extract an attribute value from available xml files. e.g liferay-version="20.0.1.5"
sort them and get the greatest value from the identified list. e.g "20.0.1.8" and store them in a variable
Was trying using python, but due to restriction on my work server. couldn't install additional packages, so couldn't use python.
Is it possible using sed/awk/bash or any way please.
file1.txt
<?xml version="1.0" encoding="utf-8"?>
<package date-created="26/11/2019" liferay-version="20.0.1.5" patch-version="5.0">
<description />
<system />
</package>file2.txt
<?xml version="1.0" encoding="utf-8"?>
<package date-created="26/11/2019" liferay-version="20.0.1.6" patch-version="6.0">
<description />
<system />
</package>file3.txt
<?xml version="1.0" encoding="utf-8"?>
<package date-created="26/11/2019" liferay-version="20.0.1.7" patch-version="7.0">
<description />
<system />
</package>file4.txt
<?xml version="1.0" encoding="utf-8"?>
<package date-created="26/11/2019" liferay-version="20.0.1.8" patch-version="8.0">
<description />
<system />
</package>ASKER CERTIFIED SOLUTION
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ASKER
Hi Pierre, another help on this one please
Once we get the latest....Is it possible to get the corresponding patch-version from the same file please
basically we are expecting "8.0"
Once we get the latest....Is it possible to get the corresponding patch-version from the same file please
basically we are expecting "8.0"
ASKER
just extended your script. May not be the correct way
lastversion=$(grep -oh 'liferay-version="[^"]*' file*.txt | sed 's/liferay-version="//' | sort -rV | head -n1); echo $lastversion
fileName=$(grep -l "$lastversion" file*.txt)
patchversion=$(grep -oh 'patch-version="[^"]*' ${fileName} | sed 's/patch-version="//' | sort -rV | head -n1); echo $patchversion ASKER
sort is not required in the 2nd scenario
lastversion=$(grep -oh 'liferay-version="[^"]*' file*.txt | sed 's/liferay-version="//' | sort -rV | head -n1); echo $lastversion
fileName=$(grep -l "$lastversion" file*.txt)
patchversion=$(grep -oh 'patch-version="[^"]*' ${fileName} | sed 's/patch-version="//'); echo $patchversion
Hey enthuguy, I do not understand exactly what you want to do. Maybe you can issue a new question.
ASKER
thanks so much for your help Pierre