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How to test if the contents of a registry key string (REG_SZ) equals ABC?

I have a VB script I'm using to perform a task that depends on the value of a registry key string value. I need to query the key and find out if the contents of a string value (REG_SZ) equals ABC.

I already use a script that checks if a registry key exists and it works fine. I can't seem to find any information on how to check if the contents of a registry key value equals ABC. I need to check if the string contains ABC - like below.

HKEY_LOCAL_MACHINE\SOFTWARE\ESD\INFO\Program REG_SZ ABC

This is what I have

REM @echo off

reg query HKEY_LOCAL_MACHINE\SOFTWARE\ESD\INFO /v Program REM >nul 2>&1

if %ERRORLEVEL% == 0 goto THERE
if %ERRORLEVEL% == 1 goto NOTTHERE

:THERE

echo APS is there.


:NOTTHERE

echo APS is not there!

Pause

Exit b/0

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This tells me that Program exists but it doesn't test that the content of Program is ABC.

Any assistance would be appreciated.

NVIT

Have you tried using the /D switch? e.g.

reg query HKEY_LOCAL_MACHINE\SOFTWARE\ESD\INFO /v Program /d "some data here"

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Bill Prew

I typically do something like this:

for /F "tokens=1-2*" %%A in ('reg query "HKEY_LOCAL_MACHINE\SOFTWARE\ESD\INFO" /V Program 2^>NUL ^| findstr /I "Program"') do set "Program=%%~C"
if /i "%Progam% EQU "ABC" (
    echo Program was "ABC"
)

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»bp

Ken Thompson

ASKER

Never mind all. I figured it out. Here it is.

REM @echo off

reg query HKEY_LOCAL_MACHINE\SOFTWARE\ESD\INFO /v Program | find.exe /c "ABC" >nul

if %ERRORLEVEL% == 0 goto THERE
if %ERRORLEVEL% == 1 goto NOTTHERE

:THERE

echo ABC is there.


:NOTTHERE

echo ABC is not there!

Pause

Exit b/0

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ASKER CERTIFIED SOLUTION

Ken Thompson

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