Hi Experts
Could you point what's needed to change from video upload to image/photo upload on this view?
Accordingly to this code:
<div id='box-video' class='col-md-5 text-center'>
<video controls style='width: 100%'>
<source id='srcVitrine' src='' />
</video>
// Change to:
<img controls style='width: 100%'>
<source id='srcVitrine' src='' />
</img>
<div class='col-md-12 form-group'>
<label for='titulo'>URL (Vídeo):</label>
<div class="input-group">
<input type='text' id='url' name='url' disabled class='form-control'/>
<span class="input-group-btn">
<button class="btn btn-primary" type="button" onclick='hotsite.vitrine.subirVideo();'><i class="fa fa-camera"></i></button>
</span>
<input type='file' id='file' name='file' style='display:none;'/>
</div>
</div>
</div>
<script>
var jqXHRData;
$(document).ready(function() {
var pars = {
_token:$('input[name="_token"]').val()
};
var resultImageUpload = function (data) {
if (!data.result.erro) {
localizacao = data.result.retorno.localizacao;
$('#url').val(localizacao);
$('#srcVitrine').attr('src', localizacao);
// This runs
$("#box-video video")[0].load();
// This doesn't run
$("#box-video img")[0].load();
return false;
} else {
hotsite.openModalCustom("Erro",'Erro ao subir vídeo.', "Entendi", "error");
return false;
}
};
$("#file").change(function () {
if (jqXHRData) {
jqXHRData.submit();
}
return false;
});
})
</script>
Select all Open in new window
Changing from video to img is needed.
But something must to be adjusted on JS code since that error arises:
Thanks in advance
Perfect!
Thank you very much.