asked on
Python - creating message
In the below script I like to add if someone guess number less than 0 or more than 20 then it should give message and terminate the program. How I can do that? thanks
import random
n = random.randint(1, 20)
guess = int(input("Enter an integer from 1 to 20: "))
while n != "guess":
print
if guess < n:
print ("guess is low")
guess = int(input("Enter an integer from 1 to 20: "))
elif guess > n:
print ("guess is high")
guess = int(input("Enter an integer from 1 to 20: "))
else:
print ("you guessed it!")
break
print
import random
n = random.randint(1, 20)
guess = int(input("Enter an integer from 1 to 20: "))
while n != "guess":
if guess < n:
print ("guess is low")
guess = int(input("Enter an integer from 1 to 20: "))
elif guess > n:
print ("guess is high")
guess = int(input("Enter an integer from 1 to 20: "))
else:
print ("you guessed it!")
break
Python
Last Comment
snhandle
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SOLUTION
THIS SOLUTION ONLY AVAILABLE TO MEMBERS.
View this solution by signing up for a free trial.
Members can start a 7-Day free trial and enjoy unlimited access to the platform.
Of course, this would be the most Pythonic form.
if Not (1 <= guess <= 20):
break
ASKER
Very helpful!!
the command you're looking for is `break`, which breaks out of a while or for loop.
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