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Python - creating message
In the below script I like to add if someone guess number less than 0 or more than 20 then it should give message and terminate the program. How I can do that? thanks
import random
n = random.randint(1, 20)
guess = int(input("Enter an integer from 1 to 20: "))
while n != "guess":
print
if guess < n:
print ("guess is low")
guess = int(input("Enter an integer from 1 to 20: "))
elif guess > n:
print ("guess is high")
guess = int(input("Enter an integer from 1 to 20: "))
else:
print ("you guessed it!")
break
print
import random
n = random.randint(1, 20)
guess = int(input("Enter an integer from 1 to 20: "))
while n != "guess":
if guess < n:
print ("guess is low")
guess = int(input("Enter an integer from 1 to 20: "))
elif guess > n:
print ("guess is high")
guess = int(input("Enter an integer from 1 to 20: "))
else:
print ("you guessed it!")
break
the command you're looking for is `break`, which breaks out of a while or for loop.
if n < 0 or n > 20: break
Like this...
import random
n = random.randint(1, 20)
guess = int(input("Enter an integer from 1 to 20: "))
while n != "guess":
if guess <=0 or guess > 20:
break
elif guess < n:
print ("guess is low")
guess = int(input("Enter an integer from 1 to 20: "))
elif guess > n:
print ("guess is high")
guess = int(input("Enter an integer from 1 to 20: "))
else:
print ("you guessed it!")
break
Two recommendations:
1. remove the quotes around guess
2. Slight tweak on Neeraj. I find that it is easier to see the inequalities if written this way.
1. remove the quotes around guess
while n != guess:
2. Slight tweak on Neeraj. I find that it is easier to see the inequalities if written this way.
while n != guess:
if guess < 1 or 20 < guess:
break
elif guess < n:
print ("guess is low")
guess = int(input("Enter an integer from 1 to 20: "))
elif guess > n:
print ("guess is high")
guess = int(input("Enter an integer from 1 to 20: "))
else:
print ("you guessed it!")
break
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