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# Python - creating message

on
In the below script I like to add if someone guess number less than 0 or more than 20 then it should give message and terminate the program. How I can do that? thanks

import random
n = random.randint(1, 20)
guess = int(input("Enter an integer from 1 to 20: "))
while n != "guess":
print
if guess < n:
print ("guess is low")
guess = int(input("Enter an integer from 1 to 20: "))
elif guess > n:
print ("guess is high")
guess = int(input("Enter an integer from 1 to 20: "))
else:
print ("you guessed it!")
break
print
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Commented:

the command you're looking for is  `break`, which breaks out of a while or for loop.

```if n < 0 or n > 20:
break```
Excel & VBA Expert
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Commented:

Like this...

```import random
n = random.randint(1, 20)
guess = int(input("Enter an integer from 1 to 20: "))

while n != "guess":
if guess <=0 or guess > 20:
break
elif guess < n:
print ("guess is low")
guess = int(input("Enter an integer from 1 to 20: "))
elif guess > n:
print ("guess is high")
guess = int(input("Enter an integer from 1 to 20: "))
else:
print ("you guessed it!")
break```
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Top Expert 2014
Commented:
Two recommendations:
1. remove the quotes around guess
``````while n != guess:
``````

2. Slight tweak on Neeraj. I find that it is easier to see the inequalities if written this way.
``````while n != guess:
if guess < 1 or 20 < guess:
break
elif guess < n:
print ("guess is low")
guess = int(input("Enter an integer from 1 to 20: "))
elif guess > n:
print ("guess is high")
guess = int(input("Enter an integer from 1 to 20: "))
else:
print ("you guessed it!")
break
``````
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Top Expert 2014

Commented:
Of course, this would be the most Pythonic form.
``````    if Not (1 <= guess <= 20):
break
``````

Commented: