asked on

I do I retrieve 2 values from a library tuple processor

In my c# application I need to split a string VOKE@NAUTILUS into 2 strings (VOKE and NAUTILUS)

I want to use the tuple below taking

input as VOKE@NAUTILUS and output as

outputvariable1 = VOKE
outputvariable2 = NAUTILUS

The Library Processor is shown below

[public Tuple<string, string> GetUsernameCompanyName(string inputstring)
{
string s1 = inputstring;
string[] s2 = s1.Split('@');
foreach (string s3 in s2)
{
// Console.WriteLine(s3);
}
string outusername = LoginDetails.staticusercode = s2[0];
string outcompanyname = LoginDetails.staticcompany = s2[1];

return new Tuple<string, string>(outusername, outcompanyname);
}[/code]

I want to initialize the processor and get the variable into 2 screen variable as below

StringSpliterProcessor2 processor2 = new StringSpliterProcessor2(UserNameValue.Text);
UserNameValue.Text = LoginDetails.staticusercode;
CompanyCodeValue.Text = LoginDetails.staticcompany;

See where i have the error below

How do i call the processor and place the 2 values in Username.Text and Companyname.Text

Grateful for any Help

olukay

AndyAinscow

Here you have a different name
public Tuple<string, string> GetUsernameCompanyName(string inputstring)
than that in your code snippet - StringSpliterProcessor2

I guess that is your problem

Olukayode Oluwole

ASKER

So what would be the correct syntax ??

Thanks

Zvonko

The correct syntax is NOT to mix string split and LoginDetails assignment.

And after you split the input text from UserNameValue then you immediately assign to same field the first part of the string!

Common! Cleanup your concept and then is your coding more readable and resolves from itself.

Removing syntax error does not help you with your logic errors.

Olukayode Oluwole

ASKER

Ok thanks. Tried to resolve the issue as advised.

Please see below

How do i get the 2 varianles realusername and realcompanyname

back from the tuple

Olukay

ASKER CERTIFIED SOLUTION

Zvonko

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AndyAinscow

Look up tuples in the help files. It seems like you have just copied a piece of code from somewhere and don't know the basics about classes it uses.

Olukayode Oluwole

ASKER

Thanks for your help

Olukay

Zvonko

You are welcome : )

Here comes a bonus:
Add a @ char at the end of inputstring.
Like this:

public Tuple<string, string> GetUsernameCompanyName(string inputstring)
        {
            string s1 = inputstring+"@";
            string[] s2 = s1.Split('@');

Open in new window

You guess why?
This way you always get two elements in s2 and don't have to worry about whether the inputstring has an @ char or not.
You will learn the benefit of it ;-)

Greetings,
Zvonko

AndyAinscow

>>This way you always get two elements in s2 and don't have to worry about whether the inputstring has an @ char or not.

Ermmm. Think long and hard about that.

Olukayode Oluwole

ASKER

It will be good to know what extra benefits one derives. But apart from
This is there a way to confirm that @ is part of string before the split.

That's

Olukay

Zvonko

The extra benefit is that you do not have to catch the error in following statement when there is no @ char is in the inputstring:

string outcompanyname = LoginDetails.staticcompany = s2[1]

Open in new window

There is no second entry if you have no @ char. If you have two @ chars then you have three entries but that is not a problem.
Having no @ char and adding one @ char is securing you from having no second entry.

You see?

Olukayode Oluwole

ASKER

Szvonko you are simply great. Thanks