entering variables into an array
I have 100 variables, var_1 to var_100
I have to transfer the content of each variable into each element of array b row 2 : b[2]
var_1 to b[2,0]
var_2 to b[2,1] and so on
I got as far as this code
--------------------------
count = 0
for i in b[2]:
if count < 100:
b[2] = var_1
count =+ 1
--------------------------
what is the best way to do this ?
I am just learning python thankyou
I have to transfer the content of each variable into each element of array b row 2 : b[2]
var_1 to b[2,0]
var_2 to b[2,1] and so on
I got as far as this code
--------------------------
count = 0
for i in b[2]:
if count < 100:
b[2] = var_1
count =+ 1
--------------------------
what is the best way to do this ?
I am just learning python thankyou
Where are these variables and their values coming from?
ASKER CERTIFIED SOLUTION
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ASKER
they are the results of calculations made on another array.
their values are data type float
their values are data type float
ASKER
Louis I am getting the error
b[2, i] = locals()[tmp]
ValueError: setting an array element with a sequence.
b[2, i] = locals()[tmp]
ValueError: setting an array element with a sequence.
with my source code above ?
ASKER
yes
the only thing I changed was 'var_' to 'result_' which is the prefix of my variables
the only thing I changed was 'var_' to 'result_' which is the prefix of my variables
ASKER
Spyder 4.0.1
Python 3.7.6 64-bit | Qt 5.9.6 | PyQt5 5.9.2 | Windows 10
Python 3.7.6 64-bit | Qt 5.9.6 | PyQt5 5.9.2 | Windows 10
ASKER
when I change this line
tmp = ('result_' + str(i+1)) to tmp = ('result_' + str(i)) (which is good)
I get the error
b[2, i] = locals()[tmp]
KeyError: 'result_0'
tmp = ('result_' + str(i+1)) to tmp = ('result_' + str(i)) (which is good)
I get the error
b[2, i] = locals()[tmp]
KeyError: 'result_0'
provide your code please, the one I copy/paste was tested on my Mac. In between, I will look about "locals()" on windows
is variable result_0 exists ?
ASKER
yes
result_0 to result_100
result_0 to result_100
could you print tmp variable just before error
ASKER
it just prints result_0
then
b[2, i] = locals()[tmp]
KeyError: 'result_0'
-------------------------------
for i in range(sl):
tmp = ('result_' + str(i))
print(tmp)
b[2, i] = locals()[tmp]
print(b[2])
then
b[2, i] = locals()[tmp]
KeyError: 'result_0'
-------------------------------
for i in range(sl):
tmp = ('result_' + str(i))
print(tmp)
b[2, i] = locals()[tmp]
print(b[2])
what is the result of the print ? what is the value of variable "sl"
ASKER
the result of the print is result_0
the value of variable sl is 100
the value of variable sl is 100
Try globals() function instead of locals(), depending where you declare result_0..100
ASKER
still same keyerror
can you provide entire code ?
I think I found : too much parenthesis.
tmp = 'result_' + str(i)
tmp = 'result_' + str(i)