I have following two equations (r and h are constants):
x=x(b)=r (cos(b)+ tan(b)sin(b)-1)+ tan(b)h (eq. 1)
a =a(x,b)= (1/r)*sqrt((h + rsin(b))^2 + (x + r - rcos(b))^2) - b-h/r (eg. 2)
to make it readable, if we assume S=Sin(b), C=Cos(b), and T=tan(b), then we get:
x=x(b)=r (C+ TS -1)+ Th <-- these forms may be useful may be not
a =a(x,b)= (1/r)*sqrt((h + rS)^2 + (x + r - rC)^2) - b-h/r;
I want to have the following functions if possible:
a(x)=....? (eq. 3)
b(x)=....? (eq. 4) <-- this one is not that important.
Question: Is it possible to find a(x) and b(x) having (eq. 1) and (eq. 4) above?
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